Squeeze lesson deals 1-8

Deal one

The defense takes four spade tricks and switches to the 3 of club.

Two-card threat 4 of diamond.

One-card threat: 10 of hearts (can be the 8 of hearts also, depends on the line you choose to play).

The threat cards situation satisfactory: as you can squeeze any defender who holds the required position.

The timing is right: the defense rectified the count for you by cashing four spade winners.

Squeeze card: a top club.

Assumption: since East satisfies the assumption, East is squeezed on the seventh trick.

Entry position satisfactory.

After losing four spade tricks and winning the club shift, cash two more club tricks.

Before playing the squeeze card, win the King and Ace of hearts.

When playing the squeeze card, watch whether both the heart Queen and Jack are played by the defense.

If both do not appear, just play the diamonds and hope either the suit splits 3-3 or, better yet, the defender originally with four was squeezed and had to discard a diamond.

Now, let’s switch between East and West cards.

Deal two

You can use the same line of play as in the previous deal.

This time West, not East will be the victim.

Being able to squeeze either defender, is the main feature of automatic squeeze.

Deal three

Rectify the count is required when the current winner count is presently wrong for the squeeze to operate and it aims to leave exactly one remaining loser before being able to execute a squeeze.

For example: If you have two losers, you have to duck a trick before playing your squeeze, in order to rectify the count of the remaining losers to one.

You lose tricks to adjust the difference between the number of tricks to be played and the number of winners available.

Remember: you lose trick (or tricks) which you have to lose anyway.

West’s preemptive bid informs you that there is a reasonable chance that East is guarding both threat cards.

So, you must assume that East holds four or more diamonds and both King and Queen of clubs.

Without the preemptive bid, it would certainly be in either hand.

Two-card threat: 8 of diamonds.

One-card threat: Jack of clubs.

The count is not rectified. You have two losers (10 tricks out of 12 remaining tricks), one too many.

After winning the spade lead, play four rounds of hearts in order to pull trumps, and concede a spade trick in order to rectify the count.

Prior to losing the spade trick, you were in a position where you had two losers (6 tricks out of 8 remaining).

After conceding the spade trick, you are in a position where you have only one loser (the same winners, but this time it is 6 out of only 7 tricks remaining.

Win whatever is led (assume a spade) and cash the remaining heart winners.

Since East satisfies the assumption, East will be squeezed when the sixth heart is played on the eighth trick.

Be careful to not discarding a diamond from dummy.

Don’t cash the Queen of diamonds, you will need it as an entry to the threat card in the suit.

After playing the squeeze card, play the club Ace. If both the King and Queen of clubs have not appeared, play the diamonds and hope for success.

In this heart contract it is best to win the first trick since East may be able to ruff a spade continuation.

If the contract had been 6NT, it would have been essential to lose the first trick.

It would have been impossible to rectify the count by losing just one trick later in the play.

Deal four

You reach Six Diamonds and West leads the King of hearts and switches to a trump at trick two.

Unless you are particularly fortunate, you must expect a loser in spades.

The count is not rectified. You have nine winners out of eleven trick remaining.

In order to rectify the count, you should ruff the third round of clubs, so you are in a position to make all the remaining tricks but one.

The timing will be then perfect.

No doubt West has the Ace of hearts, so the Queen of hearts is a one-card threat against him.

The A-10 of spades would be the two-card threat.

Assumption: You must find West in control of spades as well.

Any combination including the Queen-Jack will do, and so will any four spades, because then again, only West will be able to control the third round.

There is no problem about entries, you have good communication in spades.

The last diamond is obviously the squeeze card.

When the last diamond is led, West will be discarding in front of dummy.

Deal five

One-card threat: King of hearts. West would never underlead the Ace at the 6-level.

Two-card threat: 9 of clubs.

Assumption: The defender with three or more clubs also has the heart Ace.

Since East is known to hold the heart Ace, assume East also has three or more clubs.

The defense rectified the count for you by leading a heart and winning the first trick.

After ruffing the second round of hearts without wasting the King on either trick, pull trumps win three spade tricks, and cash the remaining diamond winners.

The last diamond winner will squeeze East on the tenth trick.

Avoid cashing the club Ace or King so that you have the communication to cash the heart King or a third club winner.

Watch for the heart Ace. If it is not discarded, play clubs and hope for success.

Deal six

One-card threat: West’s spade bid, provided you with enough information to label the spade 7 as one-card threat.

The count is not rectified, you have 11 tricks out of 13 remaining.

In order to solve that, simply duck a diamond trick.

Now you have 11 tricks out of 12 remaining, so the timing is right.

After the opening lead is ducked and the diamond Queen continuation, the diamond 10 is virtually a two-card threat, since you can reasonably assume that West led from the King, Queen, and Jack.

Assumption: West must hold the Jack of diamonds as well as five or more spades.

After ducking the opening lead and winning the second round of diamonds, win four heart tricks, the Ace of spades and four club tricks.

West is squeezed on the tenth trick.

Deal seven

West is marked with the Queen of spades. If he has the heart length as well, there would be a squeeze.

Jack of spades is a one-card threat.

6 of hearts is a two-card threat.

Squeeze card is the last diamond from your hand.

You have eleven top tricks and you need to make twelve, but you haven’t lost a trick, so you are not in the ideal position of being able to make all the remaining tricks but one.

In order to rectify the count, you should duck a spade trick at trick one.

Suppose you overlook this.

Take one

You win with Ace and run off winners. Then you lead the last diamond, but West is not embarrassed. He throws a spade and makes two more tricks.

The cards lay as you wanted, West having control of both majors.

All goes well here if you improve the timing.

It is quite easy to do that: you simply duck the first trick.

Take two

Deal eight

One-card threat: The Queen of hearts.

Two-card threat: The 5 of spades.

Assumption: West should hold the King of hearts and at least four spades.

Suppose West wins the first four club tricks, you discard a diamond, and then leads the Jack of spades.

The defense won the first four tricks, so you do not have to rectify the count.

You can win that trick with the king, cash the Ace of hearts and then cash four diamond winners.

This will force West to make three discards.

The first two will be a small spade and a small heart.

The last diamond will then function as a squeeze card against West.

If West discards the King of hearts, you can pitch the 4 of hearts from dummy, cash the Queen of hearts and then take two spade tricks.

If West discards the 6 of spades instead, you can still discard the 4 of hearts from dummy and then take three spade tricks.

Whatever West discards, you will be able to win the last three tricks and succeed in the 3NT contract.

It is important to notice that dummy discarded the 4 of hearts regardless of which card West discarded.




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